2025-03-03     2025-03-04     2025-03-05

unique admin name3 for PL

number of errors=0
number of warnings=0
country=PL
Group=chkGrpPostalCode

select distinct admincode1,admincode2,admincode3,adminname3 from zip_code where countrycode in ('PL') and admincode1 || admincode2 || admincode3 in (select admincode1 || admincode2 || admincode3 from (select distinct admincode1,admincode2,admincode3,adminname3 from zip_code where countrycode in ('PL')) t group by admincode1,admincode2,admincode3 having count(*)>1) order by admincode1,admincode2,admincode3


admincode1	admincode2	admincode3	adminname3