2025-03-04     2025-03-05     2025-03-06

unique admin name2 for LU

number of errors=0
number of warnings=0
country=LU
Group=chkGrpPostalCode

select distinct admincode1,admincode2,adminname2 from zip_code where countrycode in ('LU') and admincode1 || admincode2 in (select admincode1 || admincode2 from (select distinct admincode1,admincode2,adminname2 from zip_code where countrycode in ('LU')) t group by admincode1,admincode2 having count(*)>1) order by admincode1,admincode2


admincode1	admincode2	adminname2