2025-03-05     2025-03-06     2025-03-07

unique admin name3 for FI

number of errors=0
number of warnings=0
country=FI
Group=chkGrpPostalCode

select distinct admincode1,admincode2,admincode3,adminname3 from zip_code where countrycode in ('FI') and admincode1 || admincode2 || admincode3 in (select admincode1 || admincode2 || admincode3 from (select distinct admincode1,admincode2,admincode3,adminname3 from zip_code where countrycode in ('FI')) t group by admincode1,admincode2,admincode3 having count(*)>1) order by admincode1,admincode2,admincode3


admincode1	admincode2	admincode3	adminname3